Solved DP-2

[pratul2789]

No description provided.

[super30admin]

Strengths:

• The Paint House solution is correct and efficient.
• The code is well-structured and readable with clear comments.
• The time and space complexity are optimal for the problem.

Areas for Improvement:

• The submission includes an unrelated solution (Coin Change 2). When submitting code, ensure that only the relevant solution is provided to avoid confusion.
• For the Paint House solution, you can optimize space further by using only two arrays (for the previous and current house) instead of storing all houses. This would reduce space complexity to O(1).
• Consider adding comments to explain the DP state: what dp[i][j] represents (the minimum cost to paint house i with color j).

Suggested optimized solution for space:

class Solution(object):
    def minCost(self, costs):
        if not costs:
            return 0
        prev = costs[0]
        for i in range(1, len(costs)):
            current = [0, 0, 0]
            current[0] = costs[i][0] + min(prev[1], prev[2])
            current[1] = costs[i][1] + min(prev[0], prev[2])
            current[2] = costs[i][2] + min(prev[0], prev[1])
            prev = current
        return min(prev)