Done DP 2

[pranjay01]

No description provided.

[super30admin]

Strengths:

• The Paint House solution is efficient with O(n) time and O(1) space.
• The code is straightforward and easy to understand.
• Good use of variable names that relate to the problem.

Areas for Improvement:

• There is a syntax error in the return statement: min(red,min(green,blue)) has an extra closing parenthesis. It should be min(red, min(blue, green)) or simply min(red, blue, green).
• Consider adding comments to explain the dynamic programming approach, especially for someone who might be reading the code for the first time.
• For consistency, you might update the colors in a more symmetric way. For example, you could compute all three new values at once to avoid relying on the order of updates. However, the current method is correct.

Example of a slight improvement for clarity (optional):

for i in range(1, len(costs)):
    prev_red, prev_blue, prev_green = red, blue, green
    red = costs[i][0] + min(prev_blue, prev_green)
    blue = costs[i][1] + min(prev_red, prev_green)
    green = costs[i][2] + min(prev_red, prev_blue)

This way, you don't need to store oldBlue and oldRed separately and the logic is symmetric.

Overall, the solution for Paint House is excellent.