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35 changes: 34 additions & 1 deletion graphs/minimum_effort_path.py
Original file line number Diff line number Diff line change
@@ -1,3 +1,7 @@
from collections import defaultdict
import heapq


def min_effort_path(heights):
""" Given a 2D array of heights, write a function to return
the path with minimum effort.
Expand All @@ -15,4 +19,33 @@ def min_effort_path(heights):
int
minimum effort required to navigate the path from (0, 0) to heights[rows - 1][columns - 1]
"""
pass
graph = defaultdict(list)
if not heights:
return 0
directions = [(0, 1), (1, 0), (-1, 0), (0, -1)]
rows = len(heights)
cols = len(heights[0])

for x in range(cols):
for y in range(rows):
for direction in directions:
newx, newy = x + direction[0], y + direction[1]
if newx >= 0 and newx < cols and newy >= 0 and newy < rows:
abs_difference = abs(heights[y][x] - heights[newy][newx])
graph[(y,x)].append(((newy, newx), abs_difference))
visited = set()
min_heap = []
start = (0,0)
end = (rows-1, cols-1)
min_heap.append((0, start))
max_abs = 0
while min_heap:
cost_till, curr, = heapq.heappop(min_heap)
visited.add(curr)
max_abs = max(max_abs, cost_till)
if curr == end:
return max_abs
for next, to_reach in graph[curr]:
if next not in visited:
heapq.heappush(min_heap, (to_reach, next))
return max_abs