Given a non-empty array of integers nums, every element appears twice except for one. Find that single one.
You must implement a solution with a linear runtime complexity and use only constant extra space.
Input: nums = [2,2,1]
Output: 1
Code :
class Solution {
public int singleNumber(int[] nums) {
int result=0;
for(int i: nums)
{
result=result^i;
}
return result;
}
}